Patapa: Clues are either standard tapa clues or standard pata clues(inverted).But a clue cannot have some tapa and some pata digits.All digits represent either tapa or pata.Determine what each clue is,and solve.
Memorized tapa: Some regions have a number written in the top-left cell, which means,whenever a shaded cell in this region is adjacent to a shaded cell in a neghbouring region,that neighbouring region should have a block of shaded cells containing that shaded cell and a length equal to the clue.
Grouped dead ends:Some nodes have black dots.All dead-end shaded cells must touch atleast one of these dots.
Triangular tapa:Each small triangle is counted as a unit cell.Numbers indicate sizes of painted cell blocks(there are upto 12 triangles around every small triangle).The no 2x2 square rule works like this : No 2x2 equilateral triangle(side length 2) can have all shaded triangles.Also, no hexagon(6 triangles) can be shaded completely.
Pointless Tapa:If two shaded cells meet at a point,there must be a shaded cell they are both adjacent to.
Kinght's Tour Tapa: A knight is placed in the grid.Shade some cells using regular tapa rules.then start moving the knight such that it visits exactly one unshaded cell in every outlined region,without landing on a clue cell or a shaded cell.Also,it cannot come back to the region where it started.
Pointless tapa modified for uniqueness.
Work is progressing on these.
ReplyDeleteGrouped Dead-Ends has one answer. So does Memorized; nice one. Knight's Tour is a bit fiddly (and should be bolded in the post), but its answer is also unique.
Pointless has four, depending mostly on which one of R6C6 (two answers), R6C7, and R7C5 is shaded.
Triangular has a problem. If you don't allow side-2 triangles, there's no way for the wall to branch. Are there any shaded cells in your solution that border three other shaded cells?
As for Patapa, I'm still working on that. I know there's at least one solution, so you have that going for you.
Addendum: Patapa also has just one answer.
DeleteUm, no. That 3 in the Pointless tapa gives it the two answers I mentioned for if R6C6 is filled.
ReplyDeleteAlso, being "Pointless" doesn't drive the solution for even a single cell. I suggest moving each 1 clue into its nearby corner; then for symmetry, remove the R6C7 clue in favor of a 2 clue at R5C7.