Unfortunately, there are two solutions that differ in R56C456. Specifically, the endpoints of the segment in C5 could both point right or both point left. Splitting the square in R56C56 into two dominoes parallel to R56C4 would prevent the first option, but it might introduce more paths.
You did forget to say that, but that only means my fix won't work. I re-solved the puzzle with that rule in mind (more easily this time) and arrived at the same ambiguity. The central 2x2 square contains four turns in one solution and two turns in the other.
(As an aside, I don't think you even need that forgotten rule. There are good applications for a room with no turns.)
Unfortunately, there are two solutions that differ in R56C456. Specifically, the endpoints of the segment in C5 could both point right or both point left. Splitting the square in R56C56 into two dominoes parallel to R56C4 would prevent the first option, but it might introduce more paths.
ReplyDeleteI think the puzzle is correct. I forgot to mention that "the loop turns atleast once in every outlined region".
ReplyDeleteYou did forget to say that, but that only means my fix won't work. I re-solved the puzzle with that rule in mind (more easily this time) and arrived at the same ambiguity. The central 2x2 square contains four turns in one solution and two turns in the other.
Delete(As an aside, I don't think you even need that forgotten rule. There are good applications for a room with no turns.)
Yes,in the middle,you can shift the horizontal segments at R5C56 and R6C56 to R5C45 and R4C45.
ReplyDelete